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Design Fast Food

For One Day, Arby’s Is Paying For Fans To Get FREE Actual Sandwich Tattoos

Photo: Peter Pham

 

Every brand has its hardcore fans who will go above and beyond to profess their love for the company. This could be in the form of collecting memorabilia, getting the company to help them get married, or even tattooing the logo on them somewhere.

Arby’s is giving those who want it the chance to do the latter of those three on their dime, as for one day only, they’ll cover the charges on your themed tattoo.

The sandwich chain has partnered up with tattoo artist Miguel “Uzi” Montgomery to give Arby’s fans a free tattoo of popular Arby’s menu items — all designed by Montgomery himself.

Below is a flash sheet of tattoo designs guests can choose from.

Photo: Arby’s

The one-day promotion will be held on Saturday, Sept. 22, at Port City Tattoo in Long Beach, CA. From 11am to 8pm, the artists at Port City will be working to ensure that everyone who comes in will get their free Arby’s tattoo, though it will be limited to one tattoo per customer.

Arby’s and Montgomery created the sandwich-inspired designs as a way to give fans a way to express their love of sandwiches. They actually look pretty sweet, too.

Not too long ago, Domino’s Russia had a similar promotion (albeit reversed) where they asked fans to get a tattoo of their logo for the promise of free pizza for life. Unfortunately, they had to cut that campaign short due to the overabundance of folks willing to ink themselves for free pizza.

Still, it seems Arby’s is taking a more straightforward approach to getting their branding on fans. No promise of 100 sandwiches a year for 100 years, just a free (well-designed) tattoo. If you’re in the Long Beach area next Saturday, and want some free ink, pop your head in to Port City Tattoo. Arby’s will also be serving free sandwiches during the event.

By Peter Pham

Pete's favorite foods include pizza, tacos and pretty much any kind of breakfast. He'll usually snap a photo or two while his food cools down.